Principal Ideal Domain
A integral domain is called a principal ideal domain if every ideal is principal.
For example, both and the ring of polynomials over a field are PIDs:
Proposition
is a principal ideal domain.
Proof Suppose is a non trivial ideal. There exists at least one positive integer in it. Pick the smallest positive integer . We claim . For any , by the remainder theorem, we have for some with . Since , it follows that . As is the smallest positive integer in , we must have . Therefore .
Remark
Indeed, any Euclidean domain is a principle ideal domain. (See proposition.)
Proposition
Every field is a principal ideal domain.
Proof Let be an ideal. If is non-trivial, then it contains a non-zero element . Since is a field, is a unit, and thus . So any field only has two trivial ideals: and .
Proposition
is a principal ideal domain for any field .
Proof
Euclidean Algorithm
The gcd of polynomials , and the linear combination that gives it can be found by the following algorithm. Compute Then up to a unit is the gcd and backward substitution gives the linear combination.
Proposition
In an integral domain every prime is irreducible.
Proof Suppose is a prime with . Then implies or . Without loss of generality, suppose . By the equation, as well, so and are associates, thus is a unit.
Nilpotent
Let be a ring. is nilpotent if there is such that .
Def Idempotent Let be a ring. is idempotent if .
Proposition
If is nilpotent then is invertible.
Recall the fundamental theorem of arithmetic:
Every integer greater than can either be prime or represented uniquely as a product of prime numbers.
Link to original
Similarly for polynomials:
Theorem
Let be a field. Every non-constant polynomial in can be written uniquely (up to reordering) as for a unit and , monic irreducible and .
Both theorems are in fact one theorem:
Unique Factorization in A PID
Every principle ideal domain is a unique factorization domain.